6(3x^2-1)=3(5x^2-7)

Solution for 6(3x^2-1)=3(5x^2-7) equation:

6(3x^2-1)=3(5x^2-7)

We move all terms to the left:

6(3x^2-1)-(3(5x^2-7))=0

We multiply parentheses

18x^2-(3(5x^2-7))-6=0


We calculate terms in parentheses: -(3(5x^2-7)), so:

3(5x^2-7)

We multiply parentheses

15x^2-21

Back to the equation:

-(15x^2-21)


We get rid of parentheses

18x^2-15x^2+21-6=0

We add all the numbers together, and all the variables

3x^2+15=0

a = 3; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·3·15
Δ = -180
Delta is less than zero, so there is no solution for the equation